I'm losing my math somewhere and can't figure out where. I'm planning the battery config for my DIY 48 V powerwall using harvested 18650 cells. Let's say my baseline power usage is 2500 watts/2.5 kW, so 2500 W / 48 V isroughly 53 amps of current I need to pull from the battery/inverter (let's ignore DC to AC conversion lost for now to keep things simple). The first phase of the battery installation will be 14s245p.To figure out how much current each 18650 cell needs to provide I divided 53 A by 245 cells to get roughly 0.217 A /217 mA per cell. I thought this was right, but out of curiosity I tried another route and divided the total watts usageby3430 (the total cells in the battery for the first phase) and I got roughly0.73 watts per cell. This equates toroughly 0.195 A / 195 mA per cell (0.73 W / 3.7 V). I know 217 mA is close to 195 mA, but I imagine they would be the same if not very very close. I'm doing something wrong here; how do I properly calculate the amperage/current needed per 18650 cell in this case?