I think I understand this Batrium diagram for just using the mosfets on the Watchmon 4 to control a negative senseshunt trip breaker but could someone correct me if I am wrong.
With a 48V battery integrated with a shunt trip breaker that requires 48 volt supply forthe shunt trip:
1. The positive of the battery connects to the positive supply voltage of the Watchmon4 with a 2A fuse in line and also connects to the positive side of the trip on the breaker with a 4A fuse in line.
2. The negative side of the battery connects to the negative ground of the Watchmon 4 and to one side of the negative sense of the trip shunt breaker
3. The other lead from the sense on the trip shunt breaker connects to the input A on the Watchmon 4.
4. The output A on the Watchmon 4 connects to the negative side of the trip on the trip shunt breaker.
5. The load (inverter) is connected through the shunt trip just like any regular breaker
Is this all correct? Is the power for the shunt trip breaker being supplied by that connection of the positive side of the battery and the output A of the Watchmon 4?
Then as I understand it if I was to use a shunt trip breaker that required 24V to power it then there would be a resister in line on the positive side of the battery before it connects to the trip side of the breaker. Is this also correct?
Then the software must be set up to determine what causesthe breaker to be tripped?
And lastly, if all of what I have stated here is correct ...where does the load connect to the breaker?
Thanks as always.