SeRiusRod
Member
- Joined
- Jul 4, 2020
- Messages
- 56
Let me understand how this is calculated:
Let's say you built a 14s100p battery from perfect 2200mAh cells.
That will be a battery of a total 48v and 220Ah. => 3,7V * 2,2Ah * 1400u = 11396Wh
Then for sizing the breaker, the values to take into account would be the total amperage of the battery and the accepted/desired discharge rate of the weakest cell?
On a side note:
Per Ohms law, V1 * I1 = V2 * I2 => 48 * 220 = 230V * I2 => (48 * 220)/ 230 = 45,9Ah
230V * 45,9Ah = 10560W
So 10560Wwill be the total power available to the house? I think there's something wrong here, it's too much.
Let's say you built a 14s100p battery from perfect 2200mAh cells.
That will be a battery of a total 48v and 220Ah. => 3,7V * 2,2Ah * 1400u = 11396Wh
Then for sizing the breaker, the values to take into account would be the total amperage of the battery and the accepted/desired discharge rate of the weakest cell?
On a side note:
Per Ohms law, V1 * I1 = V2 * I2 => 48 * 220 = 230V * I2 => (48 * 220)/ 230 = 45,9Ah
230V * 45,9Ah = 10560W
So 10560Wwill be the total power available to the house? I think there's something wrong here, it's too much.