MilkMan
New member
- Joined
- Feb 20, 2019
- Messages
- 11
I know this isn't exactly abattery topic but the goal here is to save battery power by not using an inverter in my RV. I picked up an "Insignia NS-24DF310NA19 24-Inch 720p HD Smart LED TV- Fire TV Edition" that has an internal power supply. The input is 120v at0.32 amps AC. So this would potentially be around 12v and 3.2 amps DC. I've attached a picture of the power supply with some comments.
I cracked open the case and found the power supply converts the 120v AC to DC for all outputs.Itsends16.8v to the LCD panel and 12.8v to the mainboard. It appears, if I understand correctly, the mainboard feeds back 5v to the power supply when the TV is on which triggers the 16.8v for the panel.
My thoughts are to use a buck/boost converter to stabilize the +12V connectionget 16.8v from the roughly 12v to 14v my battery will provide. I "think" I found one that also has a 5v on/off switch that seemingly would be perfect for turning the 16.8v output on. (amazon.com/dp/B017SM1O98) That is if I understand the "en" port correctly. This buck/boost seems like overkill at 15 amps but it's the only one I can find with the 5v "en" port. Snagged one off ebay for $5.
For the continuous 12.8v I would use another cheaper buck/boost converter that is always on. Unless multiple variable output buck/boost converters are readily available but I couldn't find one.
To avoid parasitic drain I was thinking about adding a switch between the converters and the battery.
Important EDIT: I struck out some of my bad readings. The correct readings are in posts #13 and #15.
I cracked open the case and found the power supply converts the 120v AC to DC for all outputs.
My thoughts are to use a buck/boost converter to stabilize the +12V connection
For the continuous 12.8v I would use another cheaper buck/boost converter that is always on. Unless multiple variable output buck/boost converters are readily available but I couldn't find one.
To avoid parasitic drain I was thinking about adding a switch between the converters and the battery.
- For those more electrically inclined does this all sound correct?
- Any idea what the 4.9v dim pin is for? (See picture)
Important EDIT: I struck out some of my bad readings. The correct readings are in posts #13 and #15.