Jeremy Choy
Member
- Joined
- May 10, 2017
- Messages
- 60
Living in a city which temps go from 35c to -35c,Looking at ways to keep the batteries cool/heated. The future14s powerwall will be going into a shed which I'll insulate the cabinet where the batteries are going, looking for feedback on how to heat/cool. How much heat is required to keep it at 5 Celsius.
Here's what I'm thinking for Heating: Based on the chart below as a starting base, I'm going to take 8ft ceilingheight so that's 5ftx10ftx8ft=400cu.ft --> 400/500watts = 0.8watts/cu.ft:
Heated Cabinet will be small I would say 3ft x 6ft x 1ft. So that's 18cuft. 18cu.ft * .8 watts = 14.4 watts to heat this cabinet?
does this make sense?
Was looking at 4 *100watt 10ohm power resistors and hook them up in series and spread them throughout the cabinet for event heat distribution but that's at 90 watts. I will add a micro controller to turn on the resistors when the temperature dips below a threshold.
maths is this correct?:
V=IR 60=I*(40ohm) I=1.5A
power across total circuit=Isquared *R P = (1.5*1.5)(40) P=90Watts or 22.5 watts /resistor
The joys of living in a harsh environment.
Suggestions/opinions?
Here's what I'm thinking for Heating: Based on the chart below as a starting base, I'm going to take 8ft ceilingheight so that's 5ftx10ftx8ft=400cu.ft --> 400/500watts = 0.8watts/cu.ft:
Heated Cabinet will be small I would say 3ft x 6ft x 1ft. So that's 18cuft. 18cu.ft * .8 watts = 14.4 watts to heat this cabinet?
does this make sense?
Was looking at 4 *100watt 10ohm power resistors and hook them up in series and spread them throughout the cabinet for event heat distribution but that's at 90 watts. I will add a micro controller to turn on the resistors when the temperature dips below a threshold.
maths is this correct?:
V=IR 60=I*(40ohm) I=1.5A
power across total circuit=Isquared *R P = (1.5*1.5)(40) P=90Watts or 22.5 watts /resistor
The joys of living in a harsh environment.
Suggestions/opinions?